if N is the set of natural numbers that are factors of 16, choose the selection below that correctly shows this set in roster form
1,2,3,4,8,16
2,4,6,8,10,12,14,16
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16
2,4,8
The selection that correctly shows the set of natural numbers that are factors of 16 in roster form is:
1,2,4,8,16
suppose u={1,2,3,4,5,6,7,8,9,10} is the universal set, and p={2,4,6,8,10}. what is p'?
The complement of a set P, denoted by P', is the set of all elements in the universal set U that are not in P.
In this case, U={1,2,3,4,5,6,7,8,9,10} and P={2,4,6,8,10}.
To find P', we need to find all the elements in U that are not in P.
P' = {1,3,5,7,9}
The correct selection that shows the set of natural numbers that are factors of 16 in roster form is:
2, 4, 8
To find the set of natural numbers that are factors of 16, we need to determine which numbers can divide evenly into 16.
The factors of 16 are 1, 2, 4, 8, and 16.
So, out of the given selections:
1,2,3,4,8,16 - This includes all the factors of 16.
2,4,6,8,10,12,14,16 - This includes some numbers that are not factors of 16, such as 6, 10, 12, and 14.
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 - This includes some numbers that are not factors of 16, such as 3, 5, 6, 7, 9, 10, 11, 12, 13, 14, and 15.
2,4,8 - This includes all the factors of 16.
Therefore, the selection that correctly shows the set of natural numbers that are factors of 16 in roster form is 2,4,8.