Use the table to answer the question
Table:
6th-grade Average. Total of students
100-90. 32 65 27
89-80
79-70
What is the part to part ratio for the 6th grade averages of 100-90 to 89-80 written using a colon?
The part to part ratio for the 6th grade averages of 100-90 to 89-80 is: 32:65
To find the part-to-part ratio for the 6th-grade averages of 100-90 to 89-80, we need to consider the number of students in each group.
According to the table, the number of students in the 100-90 average range is 32 + 65 + 27 = 124.
The number of students in the 89-80 average range is not given.
Therefore, we cannot determine the part-to-part ratio without knowing the number of students in the 89-80 average range.
To determine the part-to-part ratio for the 6th-grade averages of 100-90 to 89-80 written using a colon, we need to look at the total number of students in each average range.
From the given table, we can see that the total number of students in the 100-90 average range is 32 + 65 + 27 = 124, while the total number of students in the 89-80 average range is not provided.
Since we do not have the specific total number of students in the 89-80 average range, we cannot determine the exact part-to-part ratio. However, we can still write the ratio using a colon by considering the given information.
Therefore, the part-to-part ratio for the 6th-grade averages of 100-90 to 89-80 written using a colon would be:
100-90 : 89-80
Please note that without the total number of students in the 89-80 average range, we cannot simplify or calculate the ratio further.