Use the image to answer the question.%0D%0A%0D%0A%0D%0A%0D%0AFind the coordinates of the intersection point that solves the system of these two linear equations in two variables: 2x+y=15%0D%0A2%0D%0A%0D%0A+%0D%0A%0D%0A=%0D%0A15%0D%0A and y=−x+5%0D%0A%0D%0A=%0D%0A−%0D%0A%0D%0A+%0D%0A5%0D%0A.%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A(−5, 10)%0D%0A(%0D%0A−%0D%0A5%0D%0A,%0D%0A %0D%0A10%0D%0A)%0D%0A left parenthesis negative 5 comma 10 right parenthesis%0D%0A%0D%0A(−10, 5)%0D%0A(%0D%0A−%0D%0A10%0D%0A,%0D%0A %0D%0A5%0D%0A)%0D%0A left parenthesis negative 10 comma 5 right parenthesis%0D%0A%0D%0A(5,−10)%0D%0A(%0D%0A5%0D%0A,%0D%0A−%0D%0A10%0D%0A)%0D%0A left parenthesis 5 comma negative 10 right parenthesis%0D%0A%0D%0A(10,−5)%0D%0A(%0D%0A10%0D%0A,%0D%0A−%0D%0A5%0D%0A)%0D%0Aleft parenthesis 10 comma negative 5 right parenthesis%0D%0ASkip to navigation%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0AHighlight%0D%0A

The intersection point of the two linear equations is at (-5, 10).

To find the coordinates of the intersection point, we need to solve the system of equations:

Equation 1: 2x + y = 15
Equation 2: y = -x + 5

To solve this system, we can substitute the value of y from Equation 2 into Equation 1:

2x + (-x + 5) = 15
2x - x + 5 = 15
x + 5 = 15
x = 15 - 5
x = 10

Now, substitute the value of x into either of the original equations to find the value of y. Let's use Equation 2:

y = -x + 5
y = -10 + 5
y = -5

Therefore, the coordinates of the intersection point are (10, -5).

To find the coordinates of the intersection point that solves the system of these two linear equations, we can use the method of substitution.

Given the equations:
1) 2x + y = 15
2) y = -x + 5

We can substitute the value of y from equation 2) into equation 1) to find the value of x. Let's do that:

Substitute -x + 5 for y in equation 1):
2x + (-x + 5) = 15

Now, simplify the equation by combining like terms:
2x - x + 5 = 15
x + 5 = 15

Next, isolate x by subtracting 5 from both sides:
x = 15 - 5
x = 10

Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use equation 2):

y = -x + 5
y = -(10) + 5
y = -10 + 5
y = -5

Therefore, the coordinates of the intersection point are (10, -5).