John must mount a box which is 10 3/6 inches wide. He wants to leave 7 1/2 inches on each side of the box. How many inches across will he need?
To determine how many inches across John will need, we need to subtract the space he wants to leave on each side of the box from the width of the box:
10 3/6 inches - 7 1/2 inches - 7 1/2 inches = 10 1/6 inches
Therefore, John will need approximately 10 1/6 inches across.
To find out how many inches across John will need, we can subtract the 7 1/2 inches on each side from the total width of the box.
Given:
Total width of the box = 10 3/6 inches
Space on each side = 7 1/2 inches
To calculate the remaining width, we subtract the space on each side from the total width:
10 3/6 inches - 7 1/2 inches = 5 1/6 inches
Therefore, John will need approximately 5 1/6 inches across to mount the box.
To find out how many inches across John will need, we can subtract the total amount of space he wants to leave on both sides of the box from the width of the box.
First, we need to convert all the measurements into the same format. Let's convert the width of the box, 10 3/6 inches, to a mixed fraction.
10 3/6 inches is the same as 10 + (3/6) inches. Since 1/6 can be simplified to 1/3, we can rewrite it as:
10 + (1/3) inches
Now we can add the whole number (10) and the fraction:
10 + (1/3) = 30/3 + 1/3 = 31/3
Therefore, the width of the box is 31/3 inches.
Next, we need to subtract the total space John wants to leave on both sides of the box, which is 7 1/2 inches.
Let's convert 7 1/2 inches to a mixed fraction.
7 1/2 inches is the same as 7 + (1/2) inches. Since 1/2 can be simplified to 3/6, we can rewrite it as:
7 + (3/6) inches
Now we can add the whole number (7) and the fraction:
7 + (3/6) = 42/6 + 3/6 = 45/6
Therefore, the total space John wants to leave on both sides of the box is 45/6 inches.
Now, let's subtract the space John wants to leave from the width of the box:
Width of the box - Total space to be left on both sides
31/3 inches - 45/6 inches
We need a common denominator to subtract the fractions. The least common multiple of 3 and 6 is 6.
So, let's rewrite the fractions with the common denominator of 6:
(31/3) inches = (62/6) inches
(45/6) inches = (45/6) inches
Now we can subtract:
(62/6) inches - (45/6) inches = (62 - 45) / 6 inches = 17/6 inches
Therefore, John will need 17/6 inches across to mount the box.