Suppose that the water level of a river is 45 feet after 3 days of no rain and 10 feet after 10 days of no rain. Given the two points we know: (3, 45) and (10, 10), what would the point slope equation look like?(1 point) Responses (y−45)=−5(x−3)(y−45)=−5(x−3)open paren y minus 45 close paren is equal to negative 5 times open paren x minus 3 close paren (y−3)=−5(x−45)(y−3)=−5(x−45)open paren y minus 3 close paren is equal to negative 5 times open paren x minus 45 close paren (y−10)=−5(x+10)(y−10)=−5(x+10)open paren y minus 10 close paren is equal to negative 5 times open paren x plus 10 close paren (y+10)=−5(x−10)(y+10)=−5(x−10)open paren y plus 10 close paren is equal to negative 5 times open paren x minus 10 close paren Question 3
The correct answer is: (y−45)=−5(x−3)
The point-slope equation for the given points (3, 45) and (10, 10) would look like (y - 45) = -5(x - 3).
To find the point-slope equation, we need to use the formula:
(y - y1) = m(x - x1)
Where (x1, y1) is a point on the line and m is the slope of the line.
In this case, we have two points: (3, 45) and (10, 10). To find the slope, we can use the formula:
m = (change in y) / (change in x)
m = (10 - 45) / (10 - 3)
m = -35 / 7
m = -5
Now we can substitute one of the points and the slope into the point-slope equation. Let's use the point (3, 45):
(y - 45) = -5(x - 3)
So the point-slope equation for the given two points is:
(y - 45) = -5(x - 3)