How far are you throwing the ball? Show your work to receive credit. Answers should be in simplest radical form. (2 points)
To find the distance between two points (-3,7) and (7,-3) we need to use the distance formula and solve.
Square root ((7- (-3) )^2 + (-3 - 7)^2)
= square root ((10)^2 + (-10)^2)
=square root (100 + 100)
= square root 200
=10 square root 2
So i'm throwing the ball a distance of 10 square root 2
5. What is the coordinate for the center of the four square court? Show your work to receive credit. (2 points)
To find the coordinate for the center of the four square court, we need to find the average of the x-coordinates and the average of the y-coordinates of the four corners of the court.
The four corners of the court can be represented as (-20, 20), (20, 20), (-20, -20), and (20, -20).
Average of x-coordinates = ( -20 + 20 + -20 + 20 ) / 4 = 0 / 4 = 0
Average of y-coordinates = ( 20 + 20 + -20 + -20 ) / 4 = 0 / 4 = 0
Therefore, the coordinate for the center of the four square court is (0, 0).
Since the four square court is a square, the center will be the midpoint of the two opposite corners.
Let's say the coordinates of the two opposite corners are (x1, y1) and (x2, y2).
In this case, the two opposite corners are (-1,-1) and (1,1).
To find the midpoint, we use the midpoint formula:
Midpoint = ((x1 + x2)/2, (y1 + y2)/2)
= ((-1 + 1)/2, (-1 + 1)/2)
= (0/2, 0/2)
= (0, 0)
So, the coordinate for the center of the four square court is (0,0).
To find the coordinate for the center of the four square court, we will need to find the average of the x-coordinates and the average of the y-coordinates of the four corner points.
Let's say the four corner points of the court are (-4, -4), (4, -4), (4, 4), and (-4, 4).
The x-coordinate of the center will be the average of the x-coordinates of these four points. So we add up the x-coordinates (-4 + 4 + 4 + -4) and divide by 4 (since there are 4 points):
(-4 + 4 + 4 + -4) / 4 = 0 / 4 = 0
Therefore, the x-coordinate of the center is 0.
Similarly, we can find the y-coordinate of the center by finding the average of the y-coordinates of the four points:
(-4 + -4 + 4 + 4) / 4 = 0 / 4 = 0
So the y-coordinate of the center is also 0.
Therefore, the coordinate for the center of the four square court is (0, 0).