A car with a mass of 1250 kg at 2.24 m/s and bumps into a car
Can you please provide more information about the second car?
To fully answer your question, I would need more information about the situation. Could you please provide additional details, such as the mass and velocity of the second car, as well as any information about the collision itself?
To determine what happens when a car with a mass of 1250 kg traveling at 2.24 m/s bumps into another car, we need to consider the conservation of momentum.
The momentum of an object is the product of its mass and velocity. In this case, the momentum of the first car before the collision can be calculated by multiplying its mass (1250 kg) by its initial velocity (2.24 m/s), yielding a value of 2800 kg·m/s.
Now, let's assume the second car has a mass of 1500 kg and is initially at rest (0 m/s). After the collision, the two cars become attached and move together.
To find the velocity of the combined cars after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision.
Since the second car is stationary, its initial momentum is 0 kg·m/s. Therefore, the total initial momentum of the system is 2800 kg·m/s.
Let's assume that the final velocity of the combined cars after the collision is V. The total mass of the system (cars together) is the sum of the masses of both cars, which is 1250 kg + 1500 kg = 2750 kg.
According to the conservation of momentum, the total final momentum should be equal to the total initial momentum. Mathematically, this can be expressed as:
Total initial momentum = Total final momentum
2800 kg·m/s = (2750 kg) * V
To solve for V, we divide both sides of the equation by 2750 kg:
V = 2800 kg·m/s / 2750 kg
V ≈ 1.018 m/s
Therefore, the combined cars move together with a velocity of approximately 1.018 m/s after the collision.