Is Pb—>Pb2 + 2e-oxidation or reduction
The reaction Pb -> Pb2+ + 2e- is an oxidation reaction. In oxidation, electrons are lost by a species, resulting in an increase in oxidation state. In this reaction, lead (Pb) loses two electrons to form lead(II) ions (Pb2+), so it is oxidized.
The reaction Pb → Pb2+ + 2e- is an oxidation reaction. In this reaction, the element Pb loses two electrons (oxidation) to form Pb2+.
To determine if a given chemical reaction is an oxidation or reduction, we need to identify the changes in the oxidation states of the elements involved.
In the equation Pb → Pb2+ + 2e-, the oxidation state of Pb changes from 0 to +2. Oxidation is defined as an increase in oxidation state, so Pb is oxidized in this equation.
On the other hand, the electrons (e-) are being gained, and as a general rule, gaining electrons corresponds to reduction. So, the process of Pb → Pb2+ + 2e- is a reduction.
In conclusion, the reaction Pb → Pb2+ + 2e- is a reduction.