Calculate the mole
217g of Fe2O3
To calculate the number of moles, we need to use the molar mass of Fe2O3, which is the sum of the molar masses of iron (Fe) and oxygen (O).
The molar mass of Fe is 55.845 g/mol, and the molar mass of O is 16.00 g/mol.
Fe2O3 has 2 iron atoms and 3 oxygen atoms.
Molar mass of Fe2O3 = (2 * molar mass of Fe) + (3 * molar mass of O)
= (2 * 55.845 g/mol) + (3 * 16.00 g/mol)
= 111.69 g/mol + 48.00 g/mol
= 159.69 g/mol
Now, we can calculate the number of moles:
Number of moles = mass / molar mass
= 217 g / 159.69 g/mol
≈ 1.359 moles
Therefore, 217g of Fe2O3 is approximately 1.359 moles.
To calculate the number of moles in 217g of Fe2O3, you need to know the molar mass of Fe2O3.
The molar mass of Fe2O3 can be calculated by adding up the atomic masses of its elements:
Fe: 55.85 g/mol
O: 16.00 g/mol (there are 3 oxygen atoms in Fe2O3)
Molar mass of Fe2O3 = (2 x Fe) + (3 x O)
= (2 x 55.85 g/mol) + (3 x 16.00 g/mol)
= 111.7 g/mol + 48.0 g/mol
= 159.7 g/mol
Now, you can calculate the number of moles using the formula:
Number of moles = Mass (in grams) / Molar mass
Number of moles = 217g / 159.7 g/mol
≈ 1.36 moles
Therefore, there are approximately 1.36 moles in 217g of Fe2O3.
To calculate the number of moles of a substance, you need to use its molar mass.
First, let's find the molar mass of Fe2O3:
The atomic mass of Fe (iron) is approximately 55.85 g/mol.
The atomic mass of O (oxygen) is approximately 16.00 g/mol.
Fe2O3 consists of two iron atoms (Fe) and three oxygen atoms (O), so the molar mass is calculated as follows:
Molar mass of Fe2O3 = (2 * atomic mass of Fe) + (3 * atomic mass of O)
= (2 * 55.85 g/mol) + (3 * 16.00 g/mol)
= 111.70 g/mol + 48.00 g/mol
= 159.70 g/mol
Now that we have the molar mass of Fe2O3, we can calculate the number of moles by using the formula:
Number of moles = Mass / Molar mass
Plugging in the given mass of 217 g:
Number of moles = 217 g / 159.70 g/mol
≈ 1.359 moles
Therefore, 217 g of Fe2O3 is approximately equal to 1.359 moles.