How many grams of NH; can be produced from 13.6 g of H2?
Express your answer with the appropriate units.
The balanced chemical equation for the reaction between H2 and NH3 is:
3H2 + N2 -> 2NH3
From the equation, we can see that it takes 3 moles of H2 to produce 2 moles of NH3.
To find the number of moles of NH3 that can be produced from 13.6 g of H2, we need to convert grams of H2 to moles using the molar mass of H2.
The molar mass of H2 is 2 g/mol.
Number of moles of H2 = Mass of H2 / Molar mass of H2
Number of moles of H2 = 13.6 g / 2 g/mol
Number of moles of H2 = 6.8 mol
According to the balanced chemical equation, 3 moles of H2 produce 2 moles of NH3.
Using this ratio, we can find the number of moles of NH3 that can be produced:
Number of moles of NH3 = (Number of moles of H2 / 3) * 2
Number of moles of NH3 = (6.8 mol / 3) * 2
Number of moles of NH3 = 4.53 mol
Now, we can convert moles of NH3 to grams using the molar mass of NH3.
The molar mass of NH3 is 17 g/mol.
Mass of NH3 = Number of moles of NH3 * Molar mass of NH3
Mass of NH3 = 4.53 mol * 17 g/mol
Mass of NH3 = 77.01 g
Therefore, 13.6 g of H2 can produce 77.01 g of NH3.
To determine the number of grams of NH3 that can be produced from 13.6 g of H2, we need to consider the balanced chemical equation for the reaction between H2 and NH3.
The balanced equation is:
3H2 + N2 -> 2NH3
From the balanced equation, we can see that it takes 3 moles of H2 to produce 2 moles of NH3.
To find the moles of H2, we can use its molar mass, which is 2 g/mol.
Moles of H2 = mass of H2 / molar mass of H2
= 13.6 g / 2 g/mol
= 6.8 mol
According to the balanced equation, the moles of NH3 produced will be half of the moles of H2.
Moles of NH3 = 1/2 * moles of H2
= 1/2 * 6.8 mol
= 3.4 mol
Now, we can find the mass of NH3 using its molar mass, which is 17 g/mol.
Mass of NH3 = moles of NH3 * molar mass of NH3
= 3.4 mol * 17 g/mol
= 57.8 g
Therefore, 13.6 g of H2 can produce 57.8 g of NH3.
To solve this problem, we need to use the balanced chemical equation for the reaction between H2 and NH3. The balanced equation is:
3H2 + N2 -> 2NH3
From the equation, we can see that 3 moles of H2 are needed to produce 2 moles of NH3.
First, we need to find the number of moles of H2 using its molar mass, which is 2 g/mol. To find the moles, we divide the mass (in grams) of H2 by its molar mass:
moles of H2 = mass of H2 / molar mass of H2
= 13.6 g / 2 g/mol
= 6.8 mol
Now that we have the number of moles of H2, we can use the mole ratio from the balanced equation to find the number of moles of NH3 produced. From the equation, we know that 2 moles of NH3 are produced for every 3 moles of H2.
moles of NH3 = (moles of H2) x (2 moles of NH3 / 3 moles of H2)
= 6.8 mol x (2 mol/3 mol)
= 4.53 mol
Finally, to find the mass of NH3 produced, we multiply the number of moles of NH3 by its molar mass. The molar mass of NH3 is 17 g/mol (1 nitrogen atom + 3 hydrogen atoms).
mass of NH3 = moles of NH3 x molar mass of NH3
= 4.53 mol x 17 g/mol
= 77.01 g
Therefore, 77.01 grams of NH3 can be produced from 13.6 grams of H2.