Log2. 3749
The logarithm base 2 of 3749 is approximately 11.8736.
To find the value of log2(3749), we need to use the logarithmic property that log base b of x is equal to log base c of x divided by log base c of b, where b and c are both positive numbers not equal to 1.
In this case, we want to find log base 2 of 3749. Since 2 is a power of 10 (2 = 10^log base 10 of 2), we can rewrite log base 2 of 3749 as log base 10 of 3749 divided by log base 10 of 2.
Using a calculator, we can evaluate log base 10 of 3749 to be approximately 3.5741708, and log base 10 of 2 to be 0.30103.
Therefore, log base 2 of 3749 is equal to 3.5741708 divided by 0.30103, which is approximately 11.8787.
To calculate the logarithm base 2 of a number, you can use the logarithmic identity logbX = logcX / logc b. In this case, we want to find log2(3749).
Step 1: Find the natural logarithm (ln) of 3749. You can use a scientific calculator or a math tool like Python to find the natural logarithm.
ln(3749) โ 8.2285
Step 2: Find the natural logarithm of 2.
ln(2) โ 0.6931
Step 3: Divide the result from Step 1 by the result from Step 2.
log2(3749) = ln(3749) / ln(2) โ 8.2285 / 0.6931 โ 11.8859
Therefore, the logarithm base 2 of 3749 is approximately 11.8859.