C bisects segment BE. If BC = t +1 and CE = 15 - t, what is the length of BE?
To find the length of BE, we can add the lengths of BC and CE.
BE = BC + CE
BE = (t + 1) + (15 - t)
BE = t + 1 + 15 - t
The t terms cancel out:
BE = 1 + 15
BE = 16
Therefore, the length of BE is 16.
To find the length of BE, we can use the fact that CE = BE - BC. Given that BC = t + 1 and CE = 15 - t, we can substitute them into the equation as follows:
15 - t = BE - (t + 1)
Simplifying the equation, we distribute the negative sign:
15 - t = BE - t - 1
Combine like terms:
15 - t + t + 1 = BE
16 = BE
Therefore, the length of BE is 16 units.
To find the length of BE, we need to add the lengths of BC and CE.
Given that BC = t + 1 and CE = 15 - t, we can substitute these values into the equation.
BE = BC + CE
BE = (t + 1) + (15 - t)
BE = t + 1 + 15 - t
Simplifying the equation, we combine like terms:
BE = (t - t) + (1 + 15)
BE = 16
Therefore, the length of BE is 16.