Given that (√3-5√2)(√3+2)=a+b√6. Find a and b. Show workings bit by bit using surd method

To solve this problem, we will simplify the expression (√3-5√2)(√3+2) step by step using the surd method.

First, we will apply the difference of squares formula:

(√3-5√2)(√3+2) = (√3)^2 - (5√2)^2

Simplifying further:

= 3 - 25(2)

= 3 - 50

= -47

Therefore, a = -47 and b = 0 since there is no √6 term in the simplified expression.

To find the values of a and b in the expression (√3 - 5√2)(√3 + 2) = a + b√6, we can use the surd method.

First, let's expand the expression (√3 - 5√2)(√3 + 2):

= (√3 * √3) + (√3 * 2) + (-5√2 * √3) + (-5√2 * 2)
= 3 + 2√3 - 5√6 - 10√2

Next, we combine like terms:

= (3 - 10√2) + (2√3 - 5√6)

Now, we need to express the terms involving √2 and √6 only in terms of √6. To do this, we'll multiply the coefficients of 10√2 by √2/√2 (which equals 1) and the coefficients of 5√6 by √3/√3 (which equals 1):

= (3 - 10√2 * √2/√2) + (2√3 - 5√6 * √3/√3)
= (3 - 10√4) + (2√3 - 5√18)

Simplifying further:

= 3 - 10(2) + 2√3 - 5(3√2)
= 3 - 20 + 2√3 - 15√2
= -17 + 2√3 - 15√2

So, we have a = -17 and b = 2. Therefore, the expanded expression (√3 - 5√2)(√3 + 2) = a + b√6 can be written as -17 + 2√6.

To find the values of a and b in the expression (√3-5√2)(√3+2) = a + b√6, we will use the surd method. Here's what we need to do step by step:

Step 1: Expand the expression (√3-5√2)(√3+2).

Using the difference of squares formula, we can expand this expression as follows:
(√3-5√2)(√3+2) = (√3 * √3) + (√3 * 2) + (-5√2 * √3) + (-5√2 * 2)

Simplifying this expression, we get:
= (3) + (2√3) + (-5√2√3) + (-10√2)

Step 2: Simplify the radicals.

To simplify the expression further, we need to simplify the square roots. Remember that √a * √b = √(a * b).

We can simplify the expression -5√2√3 as follows:
-5√2√3 = -5 * √(2*3) = -5√6

Applying the same logic, we can simplify -10√2 as:
-10√2 = -10 * √2 = -10√2

After simplification, the expression becomes:
= 3 + 2√3 - 5√6 - 10√2

Step 3: Reorder the expression.

To achieve the standard form a + b√6, we reorder the terms by grouping similar radicals together and the constants separately.
= (3 - 10√2) + (2√3 - 5√6)

Step 4: Identify the values of a and b.

Comparing this with the standard form a + b√6, we find:
a = 3 - 10√2
b = 2√3 - 5√6

Therefore, the values of a and b are:
a = 3 - 10√2
b = 2√3 - 5√6