solve n^2-49=0

To solve the equation n^2 - 49 = 0, we can factor the left side of the equation:

(n - 7)(n + 7) = 0

Setting each factor equal to zero, we get:

n - 7 = 0 or n + 7 = 0

Solving these equations separately:

1) n - 7 = 0
Adding 7 to both sides:
n = 7

2) n + 7 = 0
Subtracting 7 from both sides:
n = -7

Therefore, the solutions to the equation n^2 - 49 = 0 are n = 7 and n = -7.

what is the solution of x^2+64=0

To solve the equation x^2 + 64 = 0, we can first subtract 64 from both sides:

x^2 = -64

Next, we can take the square root of both sides to isolate x:

x = ±√(-64)

We can simplify the square root of -64 by recognizing that the square root of -1 is defined as the imaginary unit "i".

So, √(-64) = √(64 * -1) = √64 * √-1 = 8i

Therefore, the solutions to the equation x^2 + 64 = 0 are x = 8i and x = -8i.

solve x^2-121=0

To solve the equation x^2 - 121 = 0, we can first add 121 to both sides:

x^2 = 121

Next, we can take the square root of both sides to isolate x:

x = ±√121

The square root of 121 is 11, so the solutions to the equation x^2 - 121 = 0 are x = 11 and x = -11.

solve by factoring m^2+8m+7=0

To solve the quadratic equation m^2 + 8m + 7 = 0, we need to factorize it using the product-sum method.

The equation can be factored as follows:
(m + 7)(m + 1) = 0

To find the values of m that satisfy this equation, we can set each factor to zero and solve for m.

1) m + 7 = 0
Subtracting 7 from both sides:
m = -7

2) m + 1 = 0
Subtracting 1 from both sides:
m = -1

Therefore, the solutions to the equation m^2 + 8m + 7 = 0 are m = -7 and m = -1.

solve by factoring n^2+2n-24=0

To solve the quadratic equation n^2 + 2n - 24 = 0, we can factorize it using the product-sum method.

The equation can be factored as follows:
(n + 6)(n - 4) = 0

To find the values of n that satisfy this equation, we can set each factor to zero and solve for n.

1) n + 6 = 0
Subtracting 6 from both sides:
n = -6

2) n - 4 = 0
Adding 4 to both sides:
n = 4

Therefore, the solutions to the equation n^2 + 2n - 24 = 0 are n = -6 and n = 4.

To solve the equation n^2 - 49 = 0, we can use the method of factoring the difference of squares.

Step 1: Start with the equation n^2 - 49 = 0.

Step 2: Rewrite 49 as 7^2. The equation now becomes n^2 - 7^2 = 0.

Step 3: Recognize that this equation is in the form of a difference of squares, which can be factored as (a + b)(a - b) = 0, where a represents n and b represents 7.

So, the equation can be factored as (n + 7)(n - 7) = 0.

Step 4: Set each factor equal to zero:

n + 7 = 0 or n - 7 = 0.

Step 5: Solve for n:

For n + 7 = 0, subtract 7 from both sides: n = -7.

For n - 7 = 0, add 7 to both sides: n = 7.

Therefore, the solutions to the equation n^2 - 49 = 0 are n = -7 and n = 7.