Write y - 2 = 3/2 (x + 2) in slope-intercept form.
y = 3/2x + 6
y = 3/2 + 5x
y = 3/2x + 5
y = 3/2x + 3/2
The correct answer is y = 3/2x + 5.
To write the equation y - 2 = 3/2 (x + 2) in slope-intercept form, you need to isolate y on one side of the equation.
Step 1: Distribute the 3/2 to the terms inside the parentheses.
y - 2 = 3/2 * x + 3/2 * 2
Simplified:
y - 2 = 3/2 * x + 3
Step 2: Combine like terms on the right side of the equation.
y - 2 = 3/2 * x + 3
Simplified:
y - 2 = (3/2) x + 3
Step 3: Add 2 to both sides of the equation to isolate y.
y - 2 + 2 = (3/2) x + 3 + 2
Simplified:
y = (3/2) x + 5
Thus, the equation y - 2 = 3/2 (x + 2) in slope-intercept form is y = (3/2) x + 5.
To write the equation y - 2 = 3/2 (x + 2) in slope-intercept form, you need to isolate y on one side of the equation and rewrite it in the form y = mx + b, where m is the slope and b is the y-intercept.
First, distribute the 3/2 to both terms inside the parentheses:
y - 2 = 3/2 * x + 3/2 * 2
y - 2 = 3/2x + 3
Next, move the constant term (-2) to the right side of the equation:
y = 3/2x + 3 + 2
y = 3/2x + 5
Therefore, the equation y - 2 = 3/2 (x + 2) in slope-intercept form is y = 3/2x + 5.