r^2+8r=48
First bring the 48 to the other side of the equation
r^2+8r-48=0
Now you can use the quadratic formula.
x=-b+-sqrt(b^2-(4ac))
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So...
a=1
b=8
c=-48
Now just plug the numbers into the quadratic equation and get your two answers.
The answers are: x=-12 and x=4
Feel free to ask if you need any more help. :-)
To solve the equation r^2 + 8r = 48, follow these steps:
1. Move the 48 to the other side of the equation: r^2 + 8r - 48 = 0
2. Now you have a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = 8, and c = -48.
3. Use the quadratic formula to find the solutions for r:
r = (-b ± sqrt(b^2 - 4ac)) / (2a)
Plug in the values: r = (-(8) ± sqrt((8)^2 - 4(1)(-48))) / (2(1))
4. Calculate the values inside the square root: sqrt(64 + 192) = sqrt(256) = 16
So, the equation becomes r = (-8 ± 16) / 2
5. Simplify: r1 = (-8 + 16) / 2 = 8 / 2 = 4, and r2 = (-8 - 16) / 2 = -24 / 2 = -12
Therefore, the solutions to the equation r^2 + 8r = 48 are r = 4 and r = -12.