One molecule of bromine (Br2) and two molecules of potassium chloride (KCl) combine in a reaction. How many atoms are in the products?(1 point)
Responses
two
two
three
three
six
six
four
four
To determine the number of atoms in the products, we need to find the total number of atoms in each compound and add them together.
Starting with the reactants:
- One molecule of bromine (Br2) contains 2 bromine atoms.
- Two molecules of potassium chloride (KCl) contain 2 potassium atoms and 2 chlorine atoms each, for a total of 4 potassium atoms and 4 chlorine atoms.
Adding these together, we have:
- 2 bromine atoms + 4 potassium atoms + 4 chlorine atoms = 10 atoms in the products.
So the correct answer is six.
To determine the number of atoms in the products of the reaction, we need to first understand the balanced equation for the reaction.
The balanced equation for the reaction between one molecule of bromine (Br2) and two molecules of potassium chloride (KCl) can be written as:
Br2 + 2 KCl → 2 KBr + Cl2
In this equation, we can see that one molecule of bromine (Br2) combines with two molecules of potassium chloride (2 KCl) to form two molecules of potassium bromide (2 KBr) and one molecule of chlorine (Cl2).
Now, let's count the number of atoms in the products:
For potassium bromide (KBr), there are two atoms of potassium (K) and two atoms of bromine (Br). So, the total number of atoms in KBr is four (2 K atoms + 2 Br atoms = 4 atoms).
For chlorine (Cl2), there are two atoms of chlorine (Cl). So, the total number of atoms in Cl2 is two (2 Cl atoms).
Therefore, the total number of atoms in the products is six:
4 atoms from KBr + 2 atoms from Cl2 = 6 atoms.
Hence, the correct answer is "six".