The water level of a river is below normal levels. Its water level is at 1 1/2
meters below sea level. During the summer, the river drops another 2 1/3
meters below sea level. What is the water level at the end of summer? Remember, the elevation is below sea level. Account for this in your answer. (1 point)
To determine the water level at the end of summer, we need to add the additional drop of 2 1/3 meters to the initial level of 1 1/2 meters below sea level.
To add these two measurements, we need to find a common denominator for the fractions. The least common multiple of 2 and 3 is 6.
Converting 1 1/2 to an improper fraction: 1 1/2 = 3/2
Converting 2 1/3 to an improper fraction: 2 1/3 = 7/3
Now that we have the fractions with a common denominator, we can add them together:
3/2 + 7/3
To add these fractions, we need to find a common denominator, which in this case is 6:
(3/2) x (3/3) = 9/6
(7/3) x (2/2) = 14/6
Now we can add the fractions:
(9/6) + (14/6) = 23/6
So the water level at the end of summer is 23/6 meters below sea level.
However, to have a simpler representation, we can divide the numerator by the denominator:
23 ÷ 6 = 3 remainder 5
This means the water level at the end of summer is 3 5/6 meters below sea level.
wrong
Apologies for the mistake. Let's correct it:
The water level of the river is initially 1 1/2 meters below sea level.
The river drops another 2 1/3 meters below sea level during the summer.
To find the total drop in water level, we need to add the initial drop and the additional drop.
1 1/2 + 2 1/3
Let's convert these mixed numbers into improper fractions:
1 1/2 = (2/2 + 1/2) = 3/2
2 1/3 = (3/3 + 1/3) = 7/3
Now, we can add the fractions:
3/2 + 7/3
To add these fractions, we need to find a common denominator, which is 6:
(3/2) x (3/3) = 9/6
(7/3) x (2/2) = 14/6
Now we can add the fractions:
9/6 + 14/6 = 23/6
So the total drop in water level at the end of summer is 23/6 meters below sea level.
To simplify this fraction, we can divide the numerator by the denominator:
23 ÷ 6 = 3 remainder 5
This means the water level at the end of summer is 3 5/6 meters below sea level.
To find the water level at the end of summer, we need to add the drop during the summer to the initial water level.
The initial water level is 1 1/2 meters below sea level.
During the summer, the river drops another 2 1/3 meters below sea level.
To add these two amounts, we can convert both to improper fractions:
1 1/2 = (2*1 + 1)/2 = 3/2
2 1/3 = (3*2 + 1)/3 = 7/3
Adding the two fractions:
3/2 + 7/3 = (3*3 + 7*2)/(2*3) = 9/6 + 14/6 = 23/6
So the water level at the end of summer is 23/6 meters below sea level.
To find the water level at the end of summer, we need to add the two given depths below sea level.
The first depth is 1 1/2 meters below sea level, which can be written as -1 1/2.
The second depth is 2 1/3 meters below sea level, which can be written as -2 1/3.
To add these two depths, we can use either a number line or the concept of adding mixed numbers.
Using the number line:
Start at sea level (0 meters), move down 1 1/2 meters, and then move down another 2 1/3 meters.
0 - 1 1/2 - 2 1/3
To add the fractions, we need a common denominator. The common denominator of 2 and 3 is 6.
0 - 3/2 - 5/3
Convert 3/2 to 6ths by multiplying the numerator (3) and denominator (2) by 3:
0 - 9/6 - 5/3
Convert 5/3 to 6ths by multiplying the numerator (5) and denominator (3) by 2:
0 - 9/6 - 10/6
Now subtract the numerators:
0 - (9 - 10)/6
0 - (-1)/6
Since we subtracted a negative, it becomes addition:
0 + 1/6
The water level at the end of summer is 1/6 meters below sea level.
Therefore, the water level at the end of summer is -1/6 meters or approximately -0.17 meters below sea level.