A bird is flying at an altitude of 10 meters above ground. After 3 seconds it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate change in the birds altitude give your answer to

The nearest hundredth and remember that the bird is descending

The quotient can be interpreted as the rate of change in the bird's altitude per second.

To calculate the quotient, we need to find the change in altitude divided by the change in time.

The change in altitude is the difference between the initial altitude and the final altitude: 10 meters - 3 meters = 7 meters.

The change in time is given as 3 seconds.

Therefore, the quotient is 7 meters / 3 seconds.

To describe the rate of change, we would say that the bird is descending at a rate of approximately 2.33 meters per second.

To find the rate of change in the bird's altitude, we can calculate the difference in altitude and divide it by the time it took.

The initial altitude of the bird is 10 meters, and after 3 seconds, it settles on a branch that is 3 meters above the ground. This means the change in altitude is 10 meters - 3 meters = 7 meters.

The time taken is 3 seconds.

To find the rate of change, we divide the change in altitude by the time taken:

Rate of change = Change in altitude / Time taken
Rate of change = 7 meters / 3 seconds

Calculating this, we get:
Rate of change = 2.333...

Therefore, the rate of change in the bird's altitude, when rounded to the nearest hundredth, is approximately 2.33 meters per second.

To interpret the quotient that describes the rate change in the bird's altitude, we need to calculate the rate of descent. The altitude change is given by the difference between the initial altitude (10 meters) and the final altitude (3 meters), which is 10 - 3 = 7 meters.

The time it takes for the bird to descend is given as 3 seconds.

Now, to find the rate of descent, we divide the change in altitude by the time it takes. So, the rate of descent is 7 meters / 3 seconds ≈ 2.33 meters per second.

Interpreting the quotient to describe the rate change in the bird's altitude means that the bird is descending at a rate of approximately 2.33 meters per second.