Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5).
To find ƒ(-2), we substitute -2 into the function ƒ(x) and solve for the output.
ƒ(-2) = 3(-2) - 1
= -6 - 1
= -7
To find g(5), we substitute 5 into the function g(x) and solve for the output.
g(5) = -(5) + 6
= -5 + 6
= 1
Hence, ƒ(-2) + g(5) is equal to -7 + 1 which is equal to -6.
To find ƒ(-2), substitute -2 into the function ƒ(x) = 3x - 1:
ƒ(-2) = 3(-2) - 1
= -6 - 1
= -7
Similarly, to find g(5), substitute 5 into the function g(x) = -x + 6:
g(5) = -(5) + 6
= -5 + 6
= 1
Finally, find the sum of ƒ(-2) and g(5):
ƒ(-2) + g(5) = -7 + 1
= -6
Therefore, ƒ(-2) + g(5) = -6.
To find ƒ(-2) + g(5), we need to substitute the values of -2 and 5 into the respective functions and then perform the addition.
First, let's find ƒ(-2). Substitute -2 into the function ƒ(x) = 3x - 1:
ƒ(-2) = 3(-2) - 1
ƒ(-2) = -6 - 1
ƒ(-2) = -7
Next, let's find g(5). Substitute 5 into the function g(x) = -x + 6:
g(5) = -(5) + 6
g(5) = -5 + 6
g(5) = 1
Now, we can find ƒ(-2) + g(5) by adding the two values we just found:
ƒ(-2) + g(5) = -7 + 1
ƒ(-2) + g(5) = -6
Therefore, ƒ(-2) + g(5) equals -6.