(-6.8) x (3.4) = ?
Multiply -2 ⅕ by -8. Write as simplifed mixed number
Lake Acid has a depth of 120ft below the surfacel. Lake Placid is ⅓ as deep. How deep is Lake Placid? Use appropriate integer to account for elevation.
Find the quotient of 8 ¼ and 2 ½. Simplified fraction
A tank holds 500 gallons of water. It drains 24 gallons of water in 6 minutes. What is the change in water in 1 minute? (remember integer representation is necessary) write in 3 sentence
(-6.8) x (3.4) = -23.12
To multiply -2 ⅕ by -8, we need to convert the mixed number to an improper fraction. -2 ⅕ is equal to -11/5. Then, we multiply -11/5 by -8 to get 88/5, which simplifies to 17 ⅗.
Lake Placid is 40 feet deep. Since Lake Acid is 120 feet below the surface, Lake Placid, which is ⅓ as deep, would be 120/3 = 40 feet deep.
To find the quotient of 8 ¼ divided by 2 ½, we convert the mixed numbers to improper fractions. 8 ¼ is equal to 33/4 and 2 ½ is equal to 5/2. Then, we divide 33/4 by 5/2 to get 33/4 ÷ 5/2 = 33/4 x 2/5 = 66/20, which simplifies to 3 1/10.
The change in water in 1 minute is 24/6 = 4 gallons.
(-6.8) x (3.4) = ?
Multiply -2 ⅕ by -8. Write as simplifed mixed number
Lake Acid has a depth of 120ft below the surfacel. Lake Placid is ⅓ as deep. How deep is Lake Placid? Use appropriate integer to account for elevation.
Find the quotient of 8 ¼ and 2 ½. Simplified fraction
A tank holds 500 gallons of water. It drains 24 gallons of water in 6 minutes. What is the change in water in 1 minute? (remember integer representation is necessary) write in 4 to 5 sentence
(-6.8) x (3.4) = -23.12
To multiply -2 ⅕ by -8, we need to convert the mixed number to an improper fraction. -2 ⅕ is equal to -11/5. Then, we multiply -11/5 by -8 to get 88/5, which simplifies to 17 ⅗.
Lake Placid is 40 feet deep. Since Lake Acid is 120 feet below the surface, Lake Placid, which is ⅓ as deep, would be 120/3 = 40 feet deep.
To find the quotient of 8 ¼ divided by 2 ½, we convert the mixed numbers to improper fractions. 8 ¼ is equal to 33/4 and 2 ½ is equal to 5/2. Then, we divide 33/4 by 5/2 to get 33/4 ÷ 5/2 = 33/4 x 2/5 = 66/20, which simplifies to 3 1/10.
The tank drains 24 gallons of water in 6 minutes, so in 1 minute it drains 24/6 = 4 gallons. The change in water in 1 minute is -4 gallons, as it is being drained and the integer representation accounts for the decrease in water level.
To solve (-6.8) x (3.4), multiply the absolute values of the numbers and then determine the sign of the result. The absolute values of -6.8 and 3.4 are 6.8 and 3.4, respectively. Multiply these two numbers to get 6.8 x 3.4 = 23.12. Since both numbers being multiplied are negative, the result is positive. Therefore, (-6.8) x (3.4) = 23.12.
To multiply -2 ⅕ by -8, convert -2 ⅕ to an improper fraction first. -2 ⅕ is equivalent to -11/5. Then multiply -11/5 by -8 to get (-11/5) x (-8) = 88/5. To simplify the fraction, divide the numerator and denominator by their greatest common divisor, which is 1 in this case. Therefore, the simplified mixed number is 88/5.
Lake Acid has a depth of 120ft below the surface. Since Lake Placid is ⅓ as deep as Lake Acid, we need to multiply 120 by 1/3. Multiplying 120 by 1/3 gives us (120 x 1) / 3 = 120/3 = 40. The elevation being negative indicates the depth below a reference point, so the depth of Lake Placid is -40ft.
To find the quotient of 8 ¼ and 2 ½, convert the mixed numbers to improper fractions. 8 ¼ is equivalent to 33/4 and 2 ½ is equivalent to 5/2. Then divide 33/4 by 5/2 by multiplying the first fraction by the reciprocal of the second fraction. (33/4) / (5/2) = (33/4) x (2/5) = 66/20. To simplify the fraction, divide the numerator and denominator by their greatest common divisor, which is 2 in this case. Therefore, the simplified fraction is 33/10.
If a tank holds 500 gallons of water and drains 24 gallons in 6 minutes, we can find the amount of water that is drained in 1 minute by dividing 24 by 6. 24 divided by 6 is 4, so the tank drains 4 gallons of water in 1 minute. Since the water is being drained, the change in water in 1 minute is -4 gallons. Therefore, the change in water in 1 minute is -4.
1. To find the product of (-6.8) and (3.4), we can multiply these two numbers. Multiply the whole numbers 6 and 3, which gives us 18. Multiply the decimals 0.8 and 0.4, which gives us 0.32. Since one of the numbers is negative, the product will also be negative. Therefore, (-6.8) x (3.4) = -18.32.
2. To multiply -2 ⅕ by -8 and write it as a simplified mixed number, we first need to convert -2 ⅕ to an improper fraction. Multiply the whole number (-2) by the denominator (5), which is -10. Add this result to the numerator (1), which gives us -10 + 1 = -9. Rewrite the mixed number as an improper fraction: -2 ⅕ = -9/5. To find the product, multiply -9/5 by -8. The product is 72/5. To simplify the fraction, divide both the numerator and the denominator by their greatest common divisor, which is 1. Therefore, the simplified mixed number is -14⅖.
3. To determine the depth of Lake Placid, which is ⅓ as deep as Lake Acid, we can multiply the depth of Lake Acid (120ft) by ⅓. Multiply 120 by ⅓ to find that Lake Placid is 120 * ⅓ = 40ft deep. Since Lake Acid is 120ft below the surface, we use a negative integer to represent depth. Therefore, the depth of Lake Placid is -40ft.
4. To find the quotient of 8 ¼ and 2 ½ and write it as a simplified fraction, we first need to convert both mixed numbers to improper fractions. 8 ¼ can be written as 33/4, and 2 ½ can be written as 5/2. To find the quotient, divide 33/4 by 5/2. Invert the divisor (5/2) and multiply it by the dividend (33/4). Simplify the fraction by dividing the numerator (33) by the denominator (10). Therefore, the quotient of 8 ¼ and 2 ½ is 33/10, which is the simplified fraction.
5. To find the change in water in 1 minute when the tank holds 500 gallons of water and drains 24 gallons in 6 minutes, we need to divide the amount drained in 6 minutes (24 gallons) by the time (6 minutes) to find the rate of draining per minute. Divide 24 by 6 to find that the tank drains at a rate of 4 gallons per minute. Since the water is draining from the tank, we represent the change as a negative integer. Therefore, the change in water in 1 minute is -4 gallons.