Write the net ionic equation for the precipitation of lead() phosphate from aqueous solution:
The balanced chemical equation for the precipitation of lead(II) phosphate from aqueous solution is:
Pb(NO3)2 + 2 Na3PO4 -> Pb3(PO4)2 + 6 NaNO3.
The net ionic equation for this reaction is:
2 Pb2+ + 3 PO43- -> Pb3(PO4)2.
To determine the net ionic equation for the precipitation of lead(II) phosphate from aqueous solution, we need to identify the reactants and the products.
The reactants in this case are lead(II) ions (Pb^2+) and phosphate ions (PO4^3-). We know that lead(II) phosphate is insoluble, so it will precipitate out of solution.
The balanced chemical equation for the precipitation reaction can be written as:
Pb^2+(aq) + 3 PO4^3-(aq) → Pb3(PO4)2(s)
To write the net ionic equation, we remove any spectator ions. Spectator ions are ions that do not participate in the actual precipitation, as they are present on both sides of the equation.
In this case, the spectator ions are the ones that remain unchanged throughout the reaction. In the above equation, the spectator ion is the lead(II) ion (Pb^2+), as it does not change state or undergo a chemical reaction.
The net ionic equation, therefore, is:
3 PO4^3-(aq) → Pb3(PO4)2(s)
This equation represents the actual precipitation of lead(II) phosphate from the aqueous solution.
To write the net ionic equation for the precipitation of lead(II) phosphate from aqueous solution, we need to first determine the chemical formula for lead(II) phosphate and any soluble or insoluble products.
Lead(II) phosphate is a compound made up of the lead(II) ion, Pb²⁺, and the phosphate ion, PO₄³⁻. The solubility rules state that most phosphates are insoluble, including lead(II) phosphate. Therefore, lead(II) phosphate will precipitate out of solution.
To write the net ionic equation, we need to consider the balanced molecular equation first. When aqueous lead(II) ions react with aqueous phosphate ions, they combine to form solid lead(II) phosphate:
Pb²⁺(aq) + PO₄³⁻(aq) → Pb₃(PO₄)₂(s)
The complete ionic equation can be written by representing all the soluble compounds as their dissociated ions:
2Pb²⁺(aq) + 3PO₄³⁻(aq) → Pb₃(PO₄)₂(s)
Finally, we can write the net ionic equation by removing any spectator ions, which are ions that are present on both sides of the equation and do not participate in the reaction. In this case, the lead(II) ions, Pb²⁺, are spectator ions since they are present on both sides. The final net ionic equation is:
3PO₄³⁻(aq) → Pb₃(PO₄)₂(s)
This equation represents the actual reaction that takes place during the precipitation of lead(II) phosphate.