Use the unbalanced chemical equation to answer the question.
2NaHCO3 -› NazGOz + COz
Which of the following can be added to the products to balance the equation?
(1 point
a 02
b ch0oh
c H2
d н2о
c H2
To balance the given chemical equation:
2 NaHCO3 ⟶ Na2CO3 + CO2
We need to add a coefficient to each compound to make sure that the number of atoms of each element is the same on both sides of the equation.
Looking at the products, Na2CO3, and CO2, we can see that there are two sodium (Na) atoms, two carbon (C) atoms, and six oxygen (O) atoms.
Now, let's consider the options given and determine which one can be added to the products to balance the equation:
a) O2: This will add extra oxygen atoms to the products, but we don't need extra oxygen in this case.
b) CH3OH: This compound does not contain any of the elements found in the products (sodium, carbon, or oxygen). Therefore, it cannot be added to balance the equation.
c) H2: This compound contains hydrogen (H), but we do not need to balance hydrogen atoms since they are already balanced in the equation.
d) H2O: This compound contains hydrogen (H) and oxygen (O) atoms. We can add this to the products to balance the equation. By adding a coefficient of 2 before H2O, we can ensure that the number of oxygen atoms is equal on both sides:
2 NaHCO3 ⟶ Na2CO3 + CO2 + 2 H2O
Therefore, the correct answer is (d) H2O.
To balance a chemical equation, you need to ensure that there is an equal number of each type of atom on both sides of the equation. Let's analyze the equation 2NaHCO3 ⟶ Na2CO3 + CO2.
The reaction involves sodium bicarbonate (NaHCO3) decomposing into sodium carbonate (Na2CO3) and carbon dioxide (CO2).
Now, let's examine the answer choices:
a) O2 (oxygen gas) cannot be added to the products to balance the equation because there is no imbalance of oxygen atoms in the equation.
b) CH3OH (methanol) cannot be added to the products to balance the equation because it is not present in the given equation.
c) H2 (hydrogen gas) could potentially be added to the products to balance the equation. However, it may not be necessary since there is no imbalance of hydrogen atoms in the equation.
d) H2O (water) can be added to the products to balance the equation. By adding water to the products' side, the equation becomes 2NaHCO3 ⟶ Na2CO3 + CO2 + H2O. This balances the equation as there is now an equal number of oxygen atoms on both sides (3 on both sides) and an equal number of hydrogen atoms (2 on both sides).
Therefore, the correct answer is (d) H2O.