A chemist determines by measurements that 0.0350 moles of fluorine gas participate in a chemical reaction calculate the mass of fluorine gas that participates
Be sure your answer has correct number of significant digits in g
To calculate the mass of fluorine gas that participates in the chemical reaction, we need to use the molar mass of fluorine (F2). The molar mass of fluorine is 38.00 g/mol.
First, we calculate the mass by multiplying the number of moles by the molar mass:
mass = moles * molar mass
mass = 0.0350 mol * 38.00 g/mol
mass = 1.33 g
Therefore, the mass of fluorine gas that participates in the chemical reaction is 1.33 grams.
To calculate the mass of fluorine gas that participates in the chemical reaction, we can use the molar mass of fluorine (F₂) and the given amount of moles.
The molar mass of fluorine is 38.003 g/mol (rounded to four decimal places).
To find the mass of fluorine gas, we can use the following equation:
Mass = Moles × Molar Mass
Mass = 0.0350 moles × 38.003 g/mol
Mass = 1.330105 g
Rounded to the correct number of significant digits, the mass of fluorine gas that participates in the chemical reaction is approximately 1.33 g.
To calculate the mass of fluorine gas that participates in the chemical reaction, we'll need to use the molar mass of fluorine (F2). The molar mass of any element or compound represents the mass of one mole of that substance.
The molar mass of fluorine (F2) is approximately 38.0 g/mol. This means that one mole of fluorine gas weighs 38.0 grams.
To determine the mass of fluorine gas, we'll multiply the number of moles by the molar mass. Let's do the calculation:
Mass of fluorine gas = Number of moles × Molar mass
Mass of fluorine gas = 0.0350 moles × 38.0 g/mol
Mass of fluorine gas = 1.33 g
Therefore, the mass of fluorine gas that participates in the chemical reaction is approximately 1.33 grams.