what is the acceleration of a ball rolling 12 m/s to a STOP in 3 seconds
To calculate the acceleration of a ball rolling from 12 m/s to a stop in 3 seconds, we need to use the equation:
acceleration = (final velocity - initial velocity) / time
Where:
Initial velocity (u) = 12 m/s
Final velocity (v) = 0 m/s (since the ball comes to a stop)
Time (t) = 3 seconds
Using the given values in the equation:
acceleration = (0 m/s - 12 m/s) / 3 s
acceleration = -12 m/s / 3 s
acceleration = -4 m/s²
Therefore, the acceleration of the ball rolling from 12 m/s to a stop in 3 seconds is -4 m/s². Here, the negative sign indicates that the ball is decelerating or slowing down.
To find the acceleration of the ball, we can use the equation:
Acceleration (a) = (Final velocity - Initial velocity) / Time
Given:
Initial velocity (u) = 12 m/s
Final velocity (v) = 0 m/s
Time (t) = 3 seconds
Substituting the given values into the equation, we have:
a = (0 - 12) m/s / 3 s
Since the ball is rolling to a stop, the final velocity is 0 m/s. Now we can calculate the acceleration:
a = -12 m/s / 3 s
Simplifying:
a = -4 m/s²
Therefore, the acceleration of the ball rolling from 12 m/s to a stop in 3 seconds is -4 m/s². The negative sign indicates that the ball is decelerating.
To find the acceleration of a ball rolling to a stop, we can use the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity is 12 m/s, the final velocity is 0 m/s, and the time is 3 seconds. Plugging in these values into the formula, we get:
acceleration = (0 m/s - 12 m/s) / 3 seconds
acceleration = (-12 m/s) / 3 seconds
Now we can calculate the acceleration:
acceleration = -4 m/s^2
Therefore, the acceleration of the ball rolling to a stop is -4 m/s^2. The negative sign indicates that the velocity is decreasing.