write an equation of the ine, inpoint slope form, that pases through the given points and has the given slope
point:(8,-8); slope:3
The point slope form of a linear equation is given by:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
Substituting the given values into the equation, we have:
y - (-8) = 3(x - 8)
Simplifying the equation, we get:
y + 8 = 3x - 24
Rearranging the equation to the standard form, we have:
3x - y = 32
Therefore, the equation of the line that passes through the point (8, -8) and has a slope of 3 in point-slope form is:
y + 8 = 3(x - 8)
To find the equation of a line in point-slope form, we need a point on the line and the slope of the line. Here, the given point is (8, -8) and the slope is 3.
The point-slope form of a linear equation is: y - y1 = m(x - x1)
Where (x1, y1) is the given point and m is the slope.
Plugging in the values, we have:
y - (-8) = 3(x - 8)
Simplifying the equation gives us the final answer:
y + 8 = 3x - 24
To write the equation of the line in point-slope form, we need to use the formula y - y1 = m(x - x1), where (x1, y1) is a point on the line, and m is the slope of the line.
Given point: (8, -8)
Slope: 3
Substituting the values into the formula, we get:
y - (-8) = 3(x - 8)
Simplifying the equation further:
y + 8 = 3x - 24
Therefore, the equation of the line in point-slope form, which passes through the point (8, -8) with a slope of 3, is:
y + 8 = 3x - 24