Solve this multi-step problem. A runner completes 1/4 of a 5-mile race every 8 minutes. At the same pace, how far can the runner go in 16 minutes? (1 point)

1/8 mile
2 1/2 mile
160 mile
1/10 mile

lmao bot you wrong the answer is -480 since im here ill just give em.

1. 2/3
2. -8
3. 2 1/2
4. -480
5. 1/3 x 150 divided by 4
I did the assignment trust in Peanut baby girls

In 8 minutes, the runner completes 1/4 of a 5-mile race.

To find out how far the runner can go in 16 minutes at the same pace, we need to calculate how many 1/4 units can be completed in 16 minutes.

Since 16 minutes is twice as long as 8 minutes, the runner can complete twice the distance.

Hence, in 16 minutes, the runner can go 2/4 of a 5-mile race.

Simplifying 2/4 gives us 1/2.

Therefore, the runner can go 1/2 mile in 16 minutes.

The answer is 2 1/2 mile.

It’s 2 1/2

A water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days? (1 point)

O 480 gallons
O 80 gallons
O -480 gallons
O -80 gallons

You are dumb miroslava.

In 1 day, which is 24 hours, the water tank will decrease by 10 gallons every 3 hours.

Therefore, in 1 day, the water tank will decrease by 10 gallons for every 24/3 = 8 cycles of 3 hours.

So, in 1 day, the water tank will decrease by 10 gallons x 8 = 80 gallons.

Therefore, in 6 days, the total change in the amount of water in the tank will be 80 gallons x 6 = 480 gallons.

The answer is O 480 gallons.

Apologies for the previous incorrect response. Let's solve the problem correctly:

The water tank decreases by 10 gallons every 3 hours every day, so in 1 day, it will decrease by 10 gallons every 3 hours, a total of 24/3 = 8 times.

Therefore, in 1 day, the water tank will decrease by 10 gallons x 8 = 80 gallons.

In 6 days, the total change in the amount of water in the tank will be 80 gallons x 6 = 480 gallons.

Hence, the correct answer is O 480 gallons.

I apologize if my previous response was not satisfactory. If you have any further questions or need assistance, please let me know and I'll be happy to help.