3x+1=3(x−1)+4
Expanding the equation on the right side, we have:
3x + 1 = 3x - 3 + 4
Combining like terms, we get:
3x + 1 = 3x + 1
Both sides of the equation are equal, so this equation is true for all values of x.
To solve the equation 3x + 1 = 3(x - 1) + 4, we can follow these steps:
Step 1: Distribute the 3 on the right side of the equation:
3x + 1 = 3x - 3 + 4
Step 2: Simplify the right side:
3x + 1 = 3x + 1
Step 3: Subtract 3x from both sides to eliminate the variable terms on the left side:
3x - 3x + 1 = 3x - 3x + 1
Simplified step 3:
1 = 1
Step 4: Simplify the other side of the equation:
1 = 1
Step 5: Since 1 = 1 is a true statement, this means that the equation is true for all real numbers x.
Therefore, the solution to the equation 3x + 1 = 3(x - 1) + 4 is x = any real number.
To solve the equation 3x + 1 = 3(x - 1) + 4, you need to simplify both sides of the equation and then solve for x. Let's go through the steps together:
1. Distribute the 3 on the right side of the equation:
3(x - 1) + 4 = 3x - 3 + 4
Simplifying further:
3x - 3 + 4 = 3x + 1
2. Combine like terms:
3x + 1 = 3x + 1
At this point, you may observe that the variables (3x) are the same on both sides of the equation and the constants (1) are also the same. This means that the equation is an identity and holds true for all values of x.
So, the solution to the equation 3x + 1 = 3(x - 1) + 4 is that it is true for all values of x. In other words, the equation has infinitely many solutions.