Bertha and Vernon are competing in a diving competition. Bertha's dive ended -30 m from the starting platform Vernon's dive ended -6 m from the starting platform. How many times farther was the end of Bertha's dive thar the end of Vernon's dive? (1 point)
•120
•-36
•-24
•5
To find the difference in distance between Bertha's dive and Vernon's dive, we need to subtract the ending distances.
Bertha's dive ended -30 m from the starting platform.
Vernon's dive ended -6 m from the starting platform.
The difference in distance between the two dives is -30 - (-6) = -30 + 6 = -24 m.
Therefore, the end of Bertha's dive was 24 m farther than the end of Vernon's dive.
The answer is -24.
To find out how many times farther Bertha's dive ended from the starting platform compared to Vernon's dive, we need to calculate the ratio of the distances.
The distance of Bertha's dive from the starting platform is -30 m, and the distance of Vernon's dive from the starting platform is -6 m.
To calculate the ratio, we divide the distance of Bertha's dive by the distance of Vernon's dive.
-30 m / -6 m = 5
Therefore, the end of Bertha's dive was 5 times farther from the starting platform compared to the end of Vernon's dive.
The correct option is: 5.
To find out how many times farther the end of Bertha's dive is from the end of Vernon's dive, we need to calculate the ratio of the distances.
First, let's find the absolute value of the distances:
-30 m (Bertha) and -6 m (Vernon).
To calculate the ratio, we'll divide the distance of Bertha's dive by the distance of Vernon's dive.
|-30| / |-6|
This simplifies to:
30 / 6
Which further simplifies to:
5
The answer is 5.
Therefore, the correct option is:
• 5