What is the distance between points J and K if J is at (- 3, 2) and K is at (1, - 6)
To find the distance between two points on the coordinate plane, we can use the distance formula.
The distance formula is √((x2 - x1)^2 + (y2 - y1)^2).
Substituting the coordinates of J and K, we have:
√((1 - (-3))^2 + (-6 - 2)^2)
Simplifying, we get:
√((1 + 3)^2 + (-6 - 2)^2)
√((4)^2 + (-8)^2)
√(16 + 64)
√80
Since 80 can be simplified further, we have:
√(16 * 5)
√16 * √5
4√5
Therefore, the distance between points J and K is 4√5 units.
To find the distance between two points, we can use the distance formula. The formula is:
Distance = √((x2 - x1)² + (y2 - y1)²)
Let's apply the formula to find the distance between points J and K, where J is at (-3, 2) and K is at (1, -6).
1. Substitute the values into the formula:
Distance = √((1 - (-3))² + (-6 - 2)²)
2. Simplify:
Distance = √((1 + 3)² + (-6 - 2)²)
Distance = √(4² + (-8)²)
Distance = √(16 + 64)
Distance = √80
3. Calculate the square root of 80:
Distance ≈ 8.94
Therefore, the distance between points J and K is approximately 8.94 units.
To find the distance between two points, we can use the distance formula. The distance formula is derived from the Pythagorean theorem and is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of point J are (-3, 2) and the coordinates of point K are (1, -6). Let's substitute these values into the distance formula:
d = √((1 - (-3))^2 + (-6 - 2)^2)
Simplifying this equation:
d = √((1 + 3)^2 + (-6 - 2)^2)
= √(4^2 + (-8)^2)
= √(16 + 64)
= √80
To simplify the square root, we can find the largest perfect square that divides evenly into 80. In this case, 80 can be factored into 16 * 5. Thus, we can rewrite the equation as:
d = √(16 * 5)
= √16 * √5
= 4√5
Therefore, the distance between points J and K is 4√5 units.