Suppose 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2
). According to the law of conservation of matter, how many atoms are present in this reaction?(1 point)
Responses
10
10
15
15
20
20
30
30
According to the law of conservation of matter, the number of atoms present before and after a chemical reaction should be the same.
In this reaction, 10 atoms of carbon (C) and 20 atoms of oxygen (O) react to form 10 molecules of carbon dioxide (CO2).
To determine the total number of atoms present in this reaction, we need to calculate the number of atoms in each molecule of carbon dioxide (CO2).
Each molecule of carbon dioxide (CO2) contains 1 atom of carbon (C) and 2 atoms of oxygen (O).
Therefore, the total number of atoms in 10 molecules of carbon dioxide (CO2) is:
10 molecules CO2 x (1 atom C + 2 atoms O) = 10 atoms C + 20 atoms O.
So, according to the law of conservation of matter, there are 10 atoms of carbon (C) and 20 atoms of oxygen (O) present in this reaction.
Therefore, the correct answer is:
10 atoms
20 atoms
To determine the number of atoms present in the reaction, we need to understand the composition of the molecules involved.
In the given reaction, 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
Each carbon dioxide (CO2) molecule consists of one carbon atom (C) and two oxygen atoms (O). Therefore, in 10 molecules of carbon dioxide, there are 10 carbon atoms and 20 oxygen atoms.
To calculate the total number of atoms, we need to add the number of carbon atoms and the number of oxygen atoms together.
Number of carbon atoms = 10
Number of oxygen atoms = 20
Total number of atoms = number of carbon atoms + number of oxygen atoms
Total number of atoms = 10 + 20 = 30
Hence, according to the law of conservation of matter, there are 30 atoms present in this reaction.