Find three consecutive integers whose sum is 234
Write an equation and solve
Let's represent the three consecutive integers as x, x+1, and x+2.
The equation for their sum is:
x + (x+1) + (x+2) = 234
Combining like terms, we get:
3x + 3 = 234
Subtracting 3 from both sides:
3x = 231
Dividing both sides by 3:
x = 77
Therefore, the three consecutive integers are 77, 78, and 79.
Let's call the first integer x, the second integer (x+1), and the third integer (x+2).
The sum of these three consecutive integers is 234.
So we can write the equation as:
x + (x+1) + (x+2) = 234
Now let's solve the equation:
3x + 3 = 234
Subtract 3 from both sides:
3x = 231
Divide both sides by 3:
x = 77
Therefore, the three consecutive integers are 77, 78, and 79.
To find three consecutive integers whose sum is 234, we can set up an equation.
Let's represent the first integer as "x". Since the numbers are consecutive, the second integer would be "x + 1", and the third integer would be "x + 2".
The sum of these three consecutive integers would be:
x + (x + 1) + (x + 2) = 234
Now we can solve the equation to find the value of "x".
Combining like terms, we get:
3x + 3 = 234
Next, we can isolate the variable by subtracting 3 from both sides of the equation:
3x = 234 - 3
Simplifying further, we have:
3x = 231
Now, we can solve for "x" by dividing both sides of the equation by 3:
x = 231 / 3
Calculating the value, we find:
x = 77
Therefore, the first integer is 77. To find the second and third integers, we can substitute the value of "x" back into our representation of the consecutive numbers.
The second integer: x + 1 = 77 + 1 = 78
The third integer: x + 2 = 77 + 2 = 79
So, the three consecutive integers whose sum is 234 are 77, 78, and 79.