Which change is likely to happen to an atom of the element strontium (Sr) during bonding?

During bonding, an atom of strontium (Sr) is likely to lose two electrons from its outermost energy level to achieve a stable electron configuration.

Betsy, Carl, and Dave each live in different cities. The populations of the cities are 194,032; 23,853; and 192,034. Betsy lives in the city with the least population. Carl does not live in the city with the greatest population. What is the population of Dave's city?

To find the population of Dave's city, we need to determine which city has the greatest and least population.

We know that Betsy lives in the city with the least population. The populations are as follows:

Betsy's city population: 23,853
Carl's city population: Unknown
Dave's city population: Unknown

Next, we know that Carl does not live in the city with the greatest population. Therefore, the city with the greatest population is not Carl's city.

To determine the population of Dave's city, we can conclude that Dave's city population is the remaining city with the greatest population:

Dave's city population: 194,032

Therefore, the population of Dave's city is 194,032.

During bonding, an atom of the element strontium (Sr) is likely to lose two electrons and form a positive ion. This is because strontium belongs to Group 2 (alkaline earth metals) of the periodic table and has two valence electrons in its outermost shell. It is more energetically favorable for the strontium atom to lose these two valence electrons and achieve a stable, noble gas electron configuration. This results in the formation of a positive ion, with a charge of +2, known as a strontium ion (Sr2+).