Write 0.4x+0.2y=0.6 in slope-intercept form.(1 point)
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To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form, we need to isolate y on one side of the equation.
Let's start by subtracting 0.4x from both sides to get rid of it:
0.2y = -0.4x + 0.6
Now, divide both sides of the equation by 0.2 to solve for y:
y = (-0.4x + 0.6) / 0.2
Simplifying the right side of the equation:
y = -2x + 3
So, the equation 0.4x + 0.2y = 0.6 can be written in slope-intercept form as:
y = -2x + 3
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept, you need to solve for y.
1. Begin by isolating the y-term on one side of the equation. Subtract 0.4x from both sides:
0.2y = -0.4x + 0.6
2. Next, divide both sides of the equation by 0.2 to solve for y:
y = (-0.4x + 0.6) / 0.2
3. Simplify the right side of the equation:
y = -2x + 3
Therefore, the equation 0.4x + 0.2y = 0.6 can be written in slope-intercept form as y = -2x + 3.
To write the equation 0.4x+0.2y=0.6 in slope-intercept form, we need to isolate y on one side of the equation.
First, let's subtract 0.4x from both sides:
0.4x+0.2y-0.4x=0.6-0.4x
This simplifies to:
0.2y=0.6-0.4x
Next, divide both sides of the equation by 0.2 to isolate y:
(0.2y)/0.2=(0.6-0.4x)/0.2
This simplifies to:
y=3-2x
Therefore, the equation 0.4x+0.2y=0.6 in slope-intercept form is y=3-2x.