Slope-Intercept Form Practice
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Question
What is the slope and the y-intercept of the equation 9+272x=−32y. Write the y-intercept as an ordered pair.(1 point)
The slope is
. The y-intercept is ( ).
To find the slope and y-intercept of the equation 9+272x=−32y, we need to rearrange the equation into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
Starting with the given equation:
9 + 272x = -32y
Divide both sides by -32 to isolate y: (remember to flip the sign since we're dividing by a negative number)
(9 + 272x) / -32 = y
Simplify the right side:
y = -272x/32 - 9/32
Now we have the equation in slope-intercept form:
y = -8.5x - 0.28125
The slope is -8.5 and the y-intercept is (0, -0.28125).
To find the slope-intercept form equation of a line, we need to rearrange the given equation in the form y = mx + b, where m is the slope and b is the y-intercept.
Given equation: 9 + 272x = -32y
First, let's isolate y on one side of the equation:
-32y = 9 + 272x
To isolate y, divide both sides of the equation by -32:
y = -9/32 - 272x/32
y = -9/32 - 17x/8
Now that the equation is in the form y = mx + b, we can identify the slope and y-intercept:
The slope (m) is the coefficient of x, which is -17/8.
The y-intercept (b) is the constant term, which is -9/32.
Writing the y-intercept as an ordered pair (0, b), the y-intercept is (0, -9/32).