Graph the equation 9−x=32y using slope-intercept form.(1 point)
The equation 9 - x = 32y can be written in slope-intercept form, y = mx + b, by isolating y:
9 - x = 32y
-x = 32y - 9
-x/32 = y - 9/32
y = -x/32 + 9/32
The slope, m, is -1/32 and the y-intercept, b, is 9/32.
To graph this equation, start by plotting the y-intercept, which is the point (0, 9/32). Then, use the slope to find additional points on the line. Since the slope is -1/32, you can use the rise over run method to find other points.
If the slope is -1/32, this means that for every increase of 1 in the x-coordinate, the y-coordinate decreases by 1/32. So, starting from the y-intercept (0, 9/32), you can move 1 unit to the right and 1/32 unit down to get the next point.
Plot these points and draw a straight line through them. The graph of the equation y = -x/32 + 9/32 will be a line that passes through the y-intercept (0, 9/32) and has a negative slope.
To graph the equation 9 - x = 32y in slope-intercept form, we need to solve for y.
9 - x = 32y
Rearranging the equation, we have:
32y = 9 - x
Now we need to isolate y by dividing both sides by 32:
y = (9 - x) / 32
The equation is now in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept.
The slope (m) is the coefficient of x, which is -1:
m = -1
The y-intercept (b) is the constant term, which is 9/32 in this case:
b = 9/32
Thus, the equation graph can be created by plotting the y-intercept (0, 9/32) and using the slope to calculate additional points.