What is the slope and the y-intercept of the equation 9+272x=−32y. Write the y-intercept as an ordered pair.(1 point)
The slope is
. The y-intercept is (
).
To find the slope and y-intercept of the equation 9 + 272x = -32y, we need to rewrite the equation in slope-intercept form, y = mx + b, where m represents the slope and b represents the y-intercept.
Step 1: Start with the given equation:
9 + 272x = -32y
Step 2: Divide both sides of the equation by -32 to solve for y:
(9 + 272x) / -32 = y
Step 3: Simplify the equation:
(-9/32) - (272x/32) = y
(-9 - 272x) / 32 = y
Now, we can see that the equation is in the form y = mx + b, where the coefficient of x is the slope and the constant term is the y-intercept.
From the given equation:
The slope, m, is -272/32 or -68/8.
To find the y-intercept, we set x = 0 and solve for y:
(-9 - 272*0) / 32 = y
-9/32 = y
So the y-intercept is (-9/32, 0).
To find the slope and y-intercept of the equation, we need to rewrite it in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
Let's rewrite the equation:
9 + 272x = -32y
First, divide both sides by -32 to isolate y:
y = -272/32x - 9/32
The equation is now in slope-intercept form.
The slope is the coefficient of x, which is -272/32. Simplifying this fraction gives us -17/2.
The y-intercept is the constant term, which is -9/32.
Therefore, the slope is -17/2 and the y-intercept is (-9/32, 0).