Use the image to answer the question. An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma 4 right parenthesis and left parenthesis 1 comma 8 right parenthesis. Derive the equation of the line in slope-intercept form. (1 point)

To derive the equation of the line in slope-intercept form, we need to find the slope of the line and the y-intercept.

The slope of a line can be found using the formula:
m = (change in y) / (change in x)

In this case, the line passes through the points (0, 4) and (1, 8).

Change in y = 8 - 4 = 4
Change in x = 1 - 0 = 1

So, the slope of the line is:
m = 4/1 = 4

Now let's find the y-intercept. The y-intercept is the point where the line crosses the y-axis. From the given information, we can see that the line crosses the y-axis at the point (0, 4).

Therefore, the y-intercept is 4.

Now we have the slope (4) and the y-intercept (4), so we can write the equation of the line in slope-intercept form, which is as follows:

y = mx + b

where m is the slope and b is the y-intercept.

Plugging in the values, we get:

y = 4x + 4

Thus, the equation of the line in slope-intercept form is y = 4x + 4.

An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid downward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma 2 right parenthesis and left parenthesis 1 comma negative 1 right parenthesis.

Write the equation of the line in slope-intercept form.

(1 point)

To derive the equation of the line in slope-intercept form, we need to find the slope of the line and the y-intercept.

The slope of a line can be found using the formula:
m = (change in y) / (change in x)

In this case, the line passes through the points (0, 2) and (1, -1).

Change in y = -1 - 2 = -3
Change in x = 1 - 0 = 1

So, the slope of the line is:
m = -3/1 = -3

Now let's find the y-intercept. The y-intercept is the point where the line crosses the y-axis. From the given information, we can see that the line crosses the y-axis at the point (0, 2).

Therefore, the y-intercept is 2.

Now we have the slope (-3) and the y-intercept (2), so we can write the equation of the line in slope-intercept form, which is as follows:

y = mx + b

where m is the slope and b is the y-intercept.

Plugging in the values, we get:

y = -3x + 2

Thus, the equation of the line in slope-intercept form is y = -3x + 2.

Question

Use the image to answer the question.

An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows on both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma negative 2 right parenthesis and left parenthesis 3 comma 0 right parenthesis.

Write the equation of the line in slope-intercept form.

(1 point)

To derive the equation of the line in slope-intercept form, we need to find the slope of the line and the y-intercept.

The slope of a line can be found using the formula:
m = (change in y) / (change in x)

In this case, the line passes through the points (0, -2) and (3, 0).

Change in y = 0 - (-2) = 2
Change in x = 3 - 0 = 3

So, the slope of the line is:
m = 2/3

Now let's find the y-intercept. The y-intercept is the point where the line crosses the y-axis. From the given information, we can see that the line crosses the y-axis at the point (0, -2).

Therefore, the y-intercept is -2.

Now we have the slope (2/3) and the y-intercept (-2), so we can write the equation of the line in slope-intercept form, which is as follows:

y = mx + b

where m is the slope and b is the y-intercept.

Plugging in the values, we get:

y = (2/3)x - 2

Thus, the equation of the line in slope-intercept form is y = (2/3)x - 2.

Given the equation y=34x−2

what is the y
-intercept? Write your answer as an ordered pair.(1 point)
The y
-intercept is (
).

The y-intercept of the equation y = 34x - 2 is the point where the line crosses the y-axis. In this case, the y-intercept can be found by setting x = 0 in the equation and solving for y.

When x = 0:
y = 34(0) - 2 = -2.

Therefore, the y-intercept is (-2, 0).

So, the answer is (-2, 0).

us ure

Apologies for the confusion. Given the equation y = 34x - 2, the y-intercept is the point where the line crosses the y-axis. In this equation, the y-intercept occurs when x = 0.

Setting x = 0, we can find the y-coordinate:

y = 34(0) - 2
y = 0 - 2
y = -2

Therefore, the y-intercept is (0, -2).

So, the answer is (0, -2).

Given the equation y=34x−2

what is the y
-intercept? Write your answer as an ordered pair.(1 point)
The y
-intercept is (