Which of these describes Kepler’s third law of orbital motion?(1 point)

Responses

T2 ∝ a3
T2 ∝ a3

T3 ∝a2
T3 ∝a2

T∝a2
T∝a2

T2∝a
T2∝a

T2 ∝ a3

Which planet’s orbit was Kepler first studying when he began to develop his laws of orbital motion?(1 point)

Responses

Earth
Earth

Mars
Mars

Jupiter
Jupiter

Saturn

Mars

Which statement describes Kepler’s third law of orbital motion?(1 point)

Responses

The cube of orbital period is proportional to the square of the semi-major axis.
The cube of orbital period is proportional to the square of the semi-major axis.

The orbital period is proportional to the square of the semi-major axis.
The orbital period is proportional to the square of the semi-major axis.

The square of orbital period is proportional to the semi-major axis.
The square of orbital period is proportional to the semi-major axis.

The square of orbital period is proportional to the cube of the semi-major axis.

The cube of orbital period is proportional to the square of the semi-major axis.

Which is the best description of Earth’s orbit?(1 point)

Responses

circular
circular

highly elliptical
highly elliptical

almost circular
almost circular

parabolic
parabolic

almost circular

Which orbital shape did most scientists in the early 1600s think the planets of our solar system have?(1 point)

Responses

hyperbolic
hyperbolic

elliptical
elliptical

circular
circular

parabolic

circular

The correct description for Kepler's third law of orbital motion is "T2 ∝ a3".

To understand how to get this answer, let's break it down:

Kepler's third law states that the square of the time period of revolution of a planet around the Sun is directly proportional to the cube of its average distance from the Sun.

In mathematical terms, this can be represented as T2 ∝ a3, where T is the time period of revolution and a is the average distance from the Sun. The symbol "∝" indicates proportionality.

To determine the correct option, we need to look for the response that matches this equation. In this case, the correct option is "T2 ∝ a3".