Right equation of the line that is parallel to -21+18y=3 and passes through point (-6,-3) in point slope form
To find the equation of the line that is parallel to -21+18y=3, we first need to put the equation in slope-intercept form, y = mx + b.
Starting with -21 + 18y = 3, we can simplify it by isolating y.
18y = 3 + 21
18y = 24
y = 24/18
y = 4/3
So, the slope of the original line is 4/3.
Since the line we are looking for is parallel to the original line, it will have the same slope of 4/3.
Now, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the line. In this case, the point (-6, -3) is on the line, so we can substitute these values into the equation:
y - (-3) = (4/3)(x - (-6))
Simplifying the equation, we get:
y + 3 = (4/3)(x + 6)
This is the equation of the line that is parallel to -21+18y=3 and passes through the point (-6, -3) in point-slope form.
To find the equation of a line parallel to a given line, you need to use the same slope as the given line.
The given line equation is -21 + 18y = 3. To put it in slope-intercept form (y = mx + b), isolate y:
18y = 3 + 21
18y = 24
y = 24/18
y = 4/3
So, the slope of the given line is 4/3.
Using the point-slope form of a linear equation, the equation of the line parallel to the given line and passing through the point (-6, -3) is:
y - y1 = m(x - x1)
Substituting the values, we get:
y - (-3) = (4/3)(x - (-6))
y + 3 = (4/3)(x + 6)
Multiplying both sides by 3, to get rid of the fraction, we get:
3y + 9 = 4(x + 6)
3y + 9 = 4x + 24
Rearranging the equation to the standard form (Ax + By = C), we get:
4x - 3y = 15
So, the equation of the line parallel to the given line and passing through the point (-6, -3) in point-slope form is 4x - 3y = 15.