8th term of -.2, .4, -.8
The pattern in the given sequence is that each term alternates sign and doubles in absolute value.
The 1st term is -.2.
The 2nd term is .4 (which is the absolute value of the first term multiplied by 2).
The 3rd term is -.8 (which is the absolute value of the second term multiplied by 2).
The 4th term would be the absolute value of the third term multiplied by 2, giving 1.6.
The 5th term would be the absolute value of the fourth term multiplied by 2, giving 3.2.
The 6th term would be the absolute value of the fifth term multiplied by 2, giving 6.4.
The 7th term would be the absolute value of the sixth term multiplied by 2, giving 12.8.
The 8th term would be the absolute value of the seventh term multiplied by 2, giving 25.6.
Therefore, the 8th term of the sequence -.2, .4, -.8 is 25.6.
To find the 8th term of the sequence -.2, .4, -.8, we can observe the pattern. The common ratio between each term is -2.
Starting from the first term -.2, we can multiply each term by -2 to find the next term:
Term 1: -.2
Term 2: -.2 * -2 = .4
Term 3: .4 * -2 = -.8
Term 4: -.8 * -2 = 1.6
Term 5: 1.6 * -2 = -3.2
Term 6: -3.2 * -2 = 6.4
Term 7: 6.4 * -2 = -12.8
Term 8: -12.8 * -2 = 25.6
Therefore, the 8th term of the sequence -.2, .4, -.8 is 25.6.