a water tank decreases by 10 gallons every 3 hours every day. what is the total change in the amount of the water in the tank after 6 days
A 480 gallons
B 80 gallons
C -480 gallons
D -80 gallons
The total change in the amount of water in the tank after 6 days can be found by calculating the change for each day and then multiplying it by the number of days.
Every 3 hours, the tank decreases by 10 gallons. In one day, there are 8 sets of 3 hours (24 hours divided by 3 hours), so the tank decreases by 10 gallons * 8 = <<10*8=80>>80 gallons in a day.
Therefore, after 6 days, the tank will decrease by 80 gallons * 6 = <<80*6=480>>480 gallons.
The total change in the amount of water in the tank after 6 days is therefore 480 gallons.
Therefore, the answer is A) 480 gallons.
To find the total change in the amount of water in the tank after 6 days, we need to calculate the change per day and multiply it by the number of days.
The amount of water lost per day can be determined by dividing the total decrease of 10 gallons every 3 hours by the number of hours in a day.
10 gallons/3 hours = (10/3) gallons per hour
Since there are 24 hours in a day, the amount of water lost per day is:
(10/3) gallons per hour × 24 hours = 80 gallons per day
Now, to find the total change in the amount of water over 6 days, we multiply the amount lost per day by the number of days:
80 gallons per day × 6 days = 480 gallons.
Therefore, the correct answer is:
A) 480 gallons.