Subtract 4.66×10−5−7.34×10−7
To subtract these numbers, we need to have the same exponent for both numbers.
First, we can rewrite 7.34×10^(-7) as 0.000000734×10^(-5) to match the exponent of the first number.
Now we can subtract:
4.66×10^(-5) - 0.000000734×10^(-5)
= (4.66 - 0.000000734) × 10^(-5)
= 4.659999266 × 10^(-5)
The U.S. national debt was $2.9617×1013 in 2021 and $3.98×1011 in 1971. Find how much the debt increased in the 50-year period.
To find how much the debt increased in the 50-year period, we need to subtract the debt in 1971 from the debt in 2021.
$2.9617×10^13 - $3.98×10^11
To subtract these numbers, we need to have the same exponent for both numbers, so we need to rewrite $3.98×10^11 as $0.398×10^13.
$2.9617×10^13 - $0.398×10^13
= ($2.9617 - $0.398) × 10^13
= $2.5637×10^13
Therefore, the debt increased by $2.5637×10^13 in the 50-year period.
The U.S. national debt was $2.9617×1013 in 2021 and $3.98×1011 in 1971. Find how much the debt increased in the 50-year period. (1 point)
Responses
A. $2.9219×1013
B. $1.0183×1024
C. $3.0015×1013
D. $2.9219×1011
To find how much the debt increased in the 50-year period, we need to subtract the debt in 1971 from the debt in 2021.
$2.9617×10^13 - $3.98×10^11
To subtract these numbers, we need to have the same exponent for both numbers, so we need to rewrite $3.98×10^11 as $0.0398×10^13.
$2.9617×10^13 - $0.0398×10^13
= ($2.9617 - $0.0398) × 10^13
= $2.9219×10^13
Therefore, the debt increased by $2.9219×10^13 in the 50-year period.
So the correct option is:
A. $2.9219×10^13
The size of a hydrogen atom is about 1.2×10−10 m across. The size of an oxygen atom is 0.000000000152 m across. What is the difference between the sizes of these atoms in scientific notation?(1 point)
Responses
To find the difference between the sizes of these atoms, we need to subtract the size of the oxygen atom from the size of the hydrogen atom.
1.2×10^(-10) m - 0.000000000152 m
To subtract these numbers, we need to have the same exponent for both numbers. So we need to rewrite 0.000000000152 m as 1.52×10^(-10) m.
1.2×10^(-10) m - 1.52×10^(-10) m
= (1.2 - 1.52) × 10^(-10)
= -0.32 × 10^(-10)
However, we usually express scientific notation numbers with a coefficient between 1 and 10. Therefore, we can rewrite it as:
= -3.2 × 10^(-11)
Therefore, the difference between the sizes of these atoms is -3.2 × 10^(-11) m.
The correct response is unclear as it is not provided in the options.
Platelets and red blood cells are components of the blood. A typical platelet and red blood cell have diameters of approximately 2.33×10−6 m and 0.0000075 m, respectively. Which blood component has a bigger diameter, and approximately by how much?(1 point)
To determine which blood component has a bigger diameter and approximately by how much, we need to compare the diameters of the platelet and red blood cell.
The platelet has a diameter of 2.33×10^(-6) m.
The red blood cell has a diameter of 0.0000075 m.
To compare these values, we can write both in the same scientific notation format.
2.33×10^(-6) m = 2.33×10^(-6) m
0.0000075 m = 7.5×10^(-6) m
Comparing these values, we can see that the red blood cell has a bigger diameter of 7.5×10^(-6) m, whereas the platelet has a diameter of 2.33×10^(-6) m.
To determine the approximate difference in diameters, we can subtract the diameter of the platelet from the diameter of the red blood cell:
7.5×10^(-6) m - 2.33×10^(-6) m = 5.17×10^(-6) m
Therefore, the red blood cell has a bigger diameter than the platelet by approximately 5.17×10^(-6) m.