Use the image to answer the question.
An illustration shows Quadrant 1 of a coordinate plane. The x-axis is labeled Games and ranges from 0 to 7 in 1 unit increments. The y-axis is labeled points and ranges from 0 to 250 in increments of 50. The graph is titled Points per Game. A line connects four points plotted on the graph. The coordinates of the plotted points are left parenthesis 0 comma 0 right parenthesis, left parenthesis 3 comma 90 right parenthesis, left parenthesis 5 comma 150 right parenthesis, and left parenthesis 7 comma 210 right parenthesis.
The average basketball points per game for Player 1 are displayed in the graph. Player 2’s average points per game are represented by the equation y=35x. Which player had the highest average points per game? Enter 1 for Player 1. Enter 2 for Player 2.
(1 point)
Player
had the highest average points per game.
To determine which player had the highest average points per game, we need to compare the y-values for each player's line equation.
For Player 1, the points plotted on the graph are:
(0, 0)
(3, 90)
(5, 150)
(7, 210)
For Player 2, the equation is:
y = 35x
Let's calculate the y-values for Player 2's line at x = 3, 5, and 7:
For x = 3:
y = 35(3) = 105
For x = 5:
y = 35(5) = 175
For x = 7:
y = 35(7) = 245
Comparing the highest y-value for each player, we can see that Player 2 had the highest average points per game. Therefore, Player 2 had the highest average points per game.
Answer: 2
To determine which player had the highest average points per game, we need to compare the data for Player 1 and Player 2.
From the given information:
- Player 1's points per game are represented by the plotted points: (0, 0), (3, 90), (5, 150), (7, 210).
- Player 2's points per game are represented by the equation y = 35x.
To compare the average points per game, we can observe the y-values (points) for both players at the same x-values (games).
For Player 1:
At x = 0, y = 0
At x = 3, y = 90
At x = 5, y = 150
At x = 7, y = 210
For Player 2 (using the equation y = 35x):
At x = 0, y = 35(0) = 0
At x = 3, y = 35(3) = 105
At x = 5, y = 35(5) = 175
At x = 7, y = 35(7) = 245
Comparing the y-values at each x-value reveals that Player 2 had the higher average points per game. Therefore, Player 2 had the highest average points per game.
Player 2 had the highest average points per game. Enter 2 for Player 2.