Use the properties of operations and rules for multiplying and dividing to solve (-2)×(1-5)÷(2-3)×(-5-6)÷(3-4)
To solve the expression (-2)×(1-5)÷(2-3)×(-5-6)÷(3-4), we follow the order of operations (PEMDAS/BODMAS), which means that we will deal with parentheses first, then perform any multiplications or divisions from left to right, and finally, we will perform any additions or subtractions from left to right.
Using the properties of operations and the rules for multiplying and dividing, we simplify the expression step by step:
(-2)×(1-5)÷(2-3)×(-5-6)÷(3-4)
= (-2)×(-4)÷(-1)×(-11)÷(-1)
= 8÷(-1)×11÷(-1)
Now, let's simplify the divisions:
8 ÷ (-1) = -8
11 ÷ (-1) = -11
Substituting these results back into the expression, we have:
= -8 × -11
= 88
Therefore, the solution is 88.
To solve the expression (-2)×(1-5)÷(2-3)×(-5-6)÷(3-4), we need to follow the properties of operations and rules for multiplying and dividing.
Step 1: Simplify the expression within parentheses from left to right:
(-2)×(1-5)÷(2-3)×(-5-6)÷(3-4) is equivalent to (-2)×(-4)÷(-1)×(-11)÷(-1).
Step 2: Apply the rule for multiplying two negative numbers:
(-2)×(-4) = 8
Step 3: Simplify the expression using division:
8÷(-1) = -8
Step 4: Perform the next multiplication:
-8×(-11) = 88
Step 5: Simplify the expression using division again:
88÷(-1) = -88
Therefore, the value of the expression (-2)×(1-5)÷(2-3)×(-5-6)÷(3-4) is -88.