Joey walked east for 15 2/3 meters from home. Then, he walked west for 21 3/4 meters. How far was Joey from home? Write your answer as a mixed number only.(1 point)
Joey was meters from home.
To find the distance Joey was from home, we need to subtract the distance he walked west from the distance he walked east.
15 2/3 meters - 21 3/4 meters
To subtract these mixed numbers, let's convert them to improper fractions first.
15 2/3 = 47/3
21 3/4 = 87/4
Now we can subtract:
47/3 - 87/4
To find a common denominator, we multiply the denominators: 3 * 4 = 12
Next, we need to adjust the numerators to match the new denominator:
47/3 = (47/3) * (4/4) = 188/12
87/4 = (87/4) * (3/3) = 261/12
Now we can subtract the fractions:
188/12 - 261/12 = (188 - 261)/12 = -73/12
The result is a negative improper fraction, which means Joey ended up 73/12 meters to the west of his home.
Now let's convert this improper fraction back to a mixed number:
Divide the numerator (73) by the denominator (12): 73 ÷ 12 = 6 with a remainder of 1
The mixed number is 6 1/12.
Therefore, Joey was 6 1/12 meters from home.
To find out how far Joey is from home, we need to subtract the distance he walked west from the distance he walked east.
The distance Joey walked east is 15 2/3 meters.
The distance Joey walked west is 21 3/4 meters.
First, let's convert the mixed numbers to improper fractions:
15 2/3 = (3 * 15 + 2)/3 = 47/3
21 3/4 = (4 * 21 + 3)/4 = 87/4
Now, we can subtract the two fractions:
47/3 - 87/4 = (47 * 4 - 87 * 3) / (3 * 4) = (188 - 261) / 12 = -73/12
So, Joey is 73/12 meters away from home.
To write the answer as a mixed number, we need to divide the numerator (73) by the denominator (12):
73 ÷ 12 = 6 remainder 1
Therefore, Joey is 6 1/12 meters away from home.