A restaurant uses a 15-pound bag of flour in 4 days. Each day, the bag of flour gets lighter as more flour is used. How much does the average amount of flour in the bag change each day? (Round to the nearest hundredth.
To find the average amount of flour in the bag change each day, you need to divide the change in flour by the number of days.
If a 15-pound bag gets lighter, the change in flour each day is 15 pounds / 4 days = <<15/4=3.75>>3.75 pounds.
Rounded to the nearest hundredth, the average amount of flour in the bag change each day is 3.75 pounds. Answer: \boxed{3.75}.
A dolphin jumped above the surface of the water. It reached an altitude of 3.5 meters above the surface of the water and then dove 10 meters below the surface of the water. It went from its highest point above the water to its lowest depth in 12.5 seconds. Interpret the quotient to describe the average rate of change in the dolphin’s position. Give your answer to the nearest hundredth
To find the average rate of change in the dolphin's position, we need to divide the change in position by the change in time.
The change in position is the difference between the dolphin's highest point above the water (3.5 meters) and its lowest depth below the water (-10 meters), which is 3.5 meters - (-10 meters) = 13.5 meters.
The change in time is 12.5 seconds.
Therefore, the average rate of change in the dolphin's position is 13.5 meters / 12.5 seconds ≈ <<13.5/12.5=1.08>>1.08 meters per second.
Answer: 1.08 meters per second.
is this true
Yes, the statement is true.
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth
To find the rate of change in the squirrel's height above the ground, we divide the change in height by the change in time.
The change in height is the difference between the height of the perch (100 feet) and the height of the stored acorns (45 feet), which is 100 feet - 45 feet = 55 feet.
The change in time is 5.25 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds ≈ 10.48 feet per second.
Answer: 10.48 feet per second.
A scuba diver was at a depth of 15 meters below the surface when she saw something interesting about 10 meters lower. She made the descent in 10.1 seconds. Interpret the quotient to describe the rate of change in the diver’s depth. Give your answer to the nearest hundredth
To find the rate of change in the diver's depth, we divide the change in depth by the change in time.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.50 meters per second.
Answer: 0.50 meters per second.