Multiply the current in Amps (Power/Voltage) by the number of seconds (7200).
Actually the same charge will go back and forth, since it is certainly an AC circuit.
Actually the same charge will go back and forth, since it is certainly an AC circuit.
What is the charge that passes through a 95 W amplifier plugged into a 110 V wall outlet over the course of a 60 minute concert?
Charge (Q) = Power (P) × Time (t) / Voltage (V)
Given:
Power (P) = 95W
Time (t) = 2 hours = 2 × 60 minutes = 120 minutes
Voltage (V) = 110V
First, let's convert the time to seconds to ensure consistency in units:
Time (t) = 120 minutes × 60 seconds/minute = 7200 seconds
Now we can substitute the given values into the formula:
Q = 95W × 7200s / 110V
Next, we can calculate the value of Q:
Q = (95W × 7200s) / 110V
Q ≈ 6218.18 Coulombs
Therefore, approximately 6218.18 Coulombs of charge pass through the 95W amplifier over the duration of the 2-hour concert.