Question

An oxygen ion has 8 protons and 6 electrons. What is its charge in coulombs?

Answer 1

+2e

Answer 2

[AI-generated answer — Clown Bot]

Well, it seems like this oxygen ion has lost two of its electrons, which means it has a charge of +2. But don't worry, I promise it won't charge you any extra coulombs for its electron shortage!

Answer 3

[AI-generated answer — Step-by-Step Bot]

To determine the charge of the oxygen ion in coulombs, we need to consider the difference between the number of protons and electrons.

The charge of a single proton is equal to +1.602 x 10^-19 Coulombs, while the charge of a single electron is equal to -1.602 x 10^-19 Coulombs.

In the given oxygen ion, there are 8 protons and 6 electrons.

The total charge of the oxygen ion can be calculated as follows:

Charge = (Number of protons - Number of electrons) x (Charge of a proton)

Charge = (8 - 6) x (1.602 x 10^-19 Coulombs)

Charge = 2 x (1.602 x 10^-19 Coulombs)

Charge = 3.204 x 10^-19 Coulombs

Therefore, the charge of the oxygen ion is 3.204 x 10^-19 Coulombs.

Answer 4

[AI-generated answer — Explain Bot]

To determine the charge of an oxygen ion, we need to know the difference between the number of protons and electrons. In this case, an oxygen ion has 8 protons and 6 electrons.

Oxygen usually has 8 protons and 8 electrons. However, because this ion has 6 electrons, we can determine that it has a charge of +2, meaning it has lost two electrons.

Now, to find the charge in coulombs, we can use the elementary charge (e) as a reference. The elementary charge is approximately 1.602 x 10^-19 coulombs.

Since the oxygen ion has a charge of +2, we multiply the elementary charge by 2:

Charge in coulombs = (2 x elementary charge)

= 2 x (1.602 x 10^-19 C)

= 3.204 x 10^-19 C

Therefore, the charge of the oxygen ion is approximately 3.204 x 10^-19 coulombs.