solve
a^2-b^2/a^2-3a * 2a-6/(a+b)^2
To simplify the given expression, we can start by factoring the numerator and denominator separately.
a^2 - b^2 can be factored as (a + b)(a - b).
a^2 - 3a can be factored as a(a - 3).
2a - 6 can be factored as 2(a - 3).
(a + b)^2 is the square of the binomial (a + b), which can be expanded as (a + b)(a + b) = a^2 + 2ab + b^2.
Now, substituting the factored forms into the expression, we have:
[(a + b)(a - b) / a(a - 3)] * [2(a - 3) / (a + b)^2]
Next, we can cancel out any common factors in the numerator and denominator:
[(a + b) * (a - b) * 2 * (a - 3)] / [a * (a - 3) * (a + b)^2]
Now, we can simplify the expression further:
[(a + b)(a - b)(a - 3)] / [a(a - 3)(a + b)^2]
Finally, we can cancel out the common factors of (a - 3) from the numerator and denominator:
(a + b)(a - b) / [a(a + b)^2]
its wrong
I apologize for the mistake in my previous response. Let's go through the simplification process correctly:
Given expression: (a^2 - b^2)/(a^2 - 3a) * (2a - 6)/(a + b)^2
First, let's factor the expressions in the numerator and denominator:
a^2 - b^2 = (a + b)(a - b)
a^2 - 3a = a(a - 3)
2a - 6 = 2(a - 3)
Now, we can substitute the factored forms into the expression:
[(a + b)(a - b)/(a(a - 3))] * [(2(a - 3))/(a + b)^2]
Next, let's cancel out any common factors in the numerator and denominator:
[(a + b)(a - b) * 2 * (a - 3)] / [a * (a - 3) * (a + b)^2]
Now, we can cancel out the common factors:
[(a + b)(a - b) * 2 ] / [a * (a + b)^2]
So, the simplified expression is:
2(a + b)(a - b)/(a(a + b)^2)
bro its wrong make it simplier
Apologies for the confusion. Let's simplify the expression further.
Given expression: (a^2 - b^2)/(a^2 - 3a) * (2a - 6)/(a + b)^2
First, let's simplify the terms in the numerators and denominators:
a^2 - b^2 = (a - b)(a + b)
a^2 - 3a = a(a - 3)
2a - 6 = 2(a - 3)
Now, we can substitute the simplified forms into the expression:
[(a - b)(a + b)/(a(a - 3))] * [(2(a - 3))/(a + b)^2]
Next, let's cancel out any common factors in the numerator and denominator:
[(a - b)/(a - 3)] * [2/(a + b)]
Finally, no further simplification can be done. So the simplified expression is:
(2(a - b))/(a - 3)(a + b)
bru simplfuy
Apologies for the confusion. Let's simplify the expression further.
Given expression: (a^2 - b^2)/(a^2 - 3a) * (2a - 6)/(a + b)^2
First, let's factor the terms in the numerators and denominators:
a^2 - b^2 = (a - b)(a + b)
a^2 - 3a = a(a - 3)
2a - 6 = 2(a - 3)
Now, let's substitute the factored forms into the expression:
[(a - b)(a + b)/(a(a - 3))] * [(2(a - 3))/(a + b)^2]
Next, let's cancel out any common factors in the numerator and denominator:
[(a - b)/(a - 3)] * [2/(a + b)]
Further simplification is not possible. So the simplified expression is:
(2(a - b))/(a - 3)(a + b)
bro its still wrong
Apologies for the misunderstanding. Let's simplify the expression correctly:
Given expression: (a^2 - b^2)/(a^2 - 3a) * (2a - 6)/(a + b)^2
First, let's factor the terms in the expression:
(a^2 - b^2) can be factored as (a + b)(a - b).
(a^2 - 3a) can be factored as a(a - 3).
Now, let's substitute the factored forms into the expression:
[(a + b)(a - b) / a(a - 3)] * [(2(a - 3)) / (a + b)^2]
Next, we can simplify the expression further by canceling out the common factors:
[(a + b)(a - b) * 2] / [a(a - 3) * (a + b)^2]
Now, the expression is simplified as much as possible.